Potential barrier, reflection coefficient

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SUMMARY

The discussion centers on calculating the reflection coefficient of electrons transitioning between two metal tubes with differing potentials. Electrons with a kinetic energy of 100 eV enter tube A and encounter a potential barrier of -50V in tube B. The reflection coefficient is derived using the formula R = ((k1 - k2) / (k1 + k2))^2, where k1 and k2 are wave numbers defined by the electron's energy and the potential barrier. The calculated reflection coefficient, assuming V0 = 50 eV, is approximately 0.3, confirming the exercise's expected outcome.

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  • Understanding of quantum mechanics principles, specifically wave functions and potential barriers.
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  • Knowledge of the Schrödinger equation and its application to quantum tunneling.
  • Ability to manipulate and interpret mathematical expressions involving square roots and exponents.
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Incand
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Homework Statement


Electrons are pushed into a grounded metal tube A by the kinetic energy of 100 eV. After having gone through the tube it passes into another tube, B, at some distance from A. Tube B is kept at a potential of -50V. Calculate how many of the electrons are reflected back into the tube A. ( Assume the potential barrier is discontinuous)

Homework Equations


If ##E>V_0## for our barrier then we have the wave numbers
##k_1 = \sqrt{\frac{2mE}{\hbar^2}}## for ##x<0## and
##k_2 = \sqrt{\frac{2m[E-V_0]}{\hbar^2}}##
for the wave functions
##\Psi_1 = Ae^{ik_1x}+Be^{-ik_1x}## for ##x < 0## and
##\Psi_2 = Ce^{ik_2x}## for ##x>0##.

The reflection coefficient is then
##R = \left(\frac{k_1-k_2}{k_1+k_2}\right)^2##.

The Attempt at a Solution


I have an electric potential difference of ##50V##, somehow I need to convert this into an potential energy but I have no idea how to do that so I don't even know if ##E>V_0## or not and the above formulas are applicable.

Assuming they are I can simply ##R## as
##R = \left( \frac{\sqrt{E}-\sqrt{E-V_0}}{\sqrt{E}-V_0} \right)^2##.
Now I don't know ##V_0## but let's guess ##V_0 = 50eV## (seeing the number 50 in the question!) then
##R=\left( \frac{\sqrt{100}-\sqrt{50}}{\sqrt{100}+\sqrt{50}} \right)^2\approx 0.3##
which agrees with the answer to the exercise but I have no idea if ##V_0 = 50eV## or why that is.
 
Physics news on Phys.org
Potential energy is ##qV## !
 
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Likes   Reactions: Incand
BvU said:
Potential energy is ##qV## !
Thanks, I suspected that but wasn't sure!
 

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