Potential difference and electron speed

[Kris1120]

Homework Statement

Through what potential difference would an electron need to be accelerated for it to achieve a speed of 5.8% of the speed of light (2.99792x10^8 m/s), starting from rest?

Homework Equations

E=Vq
E=.5mv^2

The Attempt at a Solution

Vq=.5mv^2

V=(.5mv^2)/q

V=(.5 * 9.10939e-3 kg * 1.73879e7^2 m/s) / 1.60218e-19 C

V=8.59493e30 V

 

[alphysicist]

Hi Kris1120,

Homework Statement

Through what potential difference would an electron need to be accelerated for it to achieve a speed of 5.8% of the speed of light (2.99792x10^8 m/s), starting from rest?

Homework Equations

E=Vq
E=.5mv^2

The Attempt at a Solution

Vq=.5mv^2

V=(.5mv^2)/q

V=(.5 * 9.10939e-3 kg * 1.73879e7^2 m/s) / 1.60218e-19 C

V=8.59493e30 V

The electron mass you are using is incorrect.

 

[Kris1120]

OMG what a silly mistake! Thank you so much!