An electron must be accelerated through a potential difference of approximately 8.59493e30 volts to achieve a speed of 5.8% of the speed of light (2.99792x10^8 m/s) starting from rest. The calculations utilize the equations E=Vq and E=0.5mv^2, where the mass of the electron is 9.10939e-31 kg and the charge is 1.60218e-19 C. A critical error was identified in the mass value used during the calculations, which significantly impacted the results.
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Kris1120 said:Homework Statement
Through what potential difference would an electron need to be accelerated for it to achieve a speed of 5.8% of the speed of light (2.99792x10^8 m/s), starting from rest?
Homework Equations
E=Vq
E=.5mv^2
The Attempt at a Solution
Vq=.5mv^2
V=(.5mv^2)/q
V=(.5 * 9.10939e-3 kg * 1.73879e7^2 m/s) / 1.60218e-19 C
V=8.59493e30 V