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Homework Help: Potential difference and electron speed

  1. Sep 10, 2008 #1
    1. The problem statement, all variables and given/known data

    Through what potential difference would an electron need to be accelerated for it to achieve a speed of 5.8% of the speed of light (2.99792x10^8 m/s), starting from rest?

    2. Relevant equations

    E=Vq
    E=.5mv^2


    3. The attempt at a solution

    Vq=.5mv^2

    V=(.5mv^2)/q

    V=(.5 * 9.10939e-3 kg * 1.73879e7^2 m/s) / 1.60218e-19 C

    V=8.59493e30 V
     
  2. jcsd
  3. Sep 10, 2008 #2

    alphysicist

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    Homework Helper

    Hi Kris1120,

    The electron mass you are using is incorrect.
     
  4. Sep 11, 2008 #3
    OMG what a silly mistake! Thank you so much!
     
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