Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Homework Help: Potential difference inside a spherical shell

  1. Oct 4, 2011 #1
    1. The problem statement, all variables and given/known data

    A top half of a spherical shell has radius R and uniform charge density sigma. Find the potential difference V(b)-V(a) between point b at the north pole, and point a at the center of the sphere.

    2. Relevant equations



    3. The attempt at a solution

    [itex]\oint E ds = \frac{\int \sigma ds}{\epsilon_{0}}[/itex]

    I integrated sigma ds from 0 to 2pi and 0 to pi/2, and got the total surface area as 2pi r^2. Now I want to solve for E, and then use [itex]-\int E dl[/itex] to give me the potential difference, but what does the left hand side of my original equation equal?

    E is uniform along the surface, so I can pull it out of the integral and be left with the integral of ds. But wouldnt that be 2pir^2 as well? I'd be left with E=sigma/epsilon0
     
  2. jcsd
  3. Oct 5, 2011 #2
    Would it be easier to integrate the potential directly?

    V(r) = C * ∫ σ(r')*da'/[r - r']
     
Share this great discussion with others via Reddit, Google+, Twitter, or Facebook