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Potential in a quadrupole

  1. Feb 27, 2012 #1

    I have a problem where a charged particle is residing in a two dimensional quadrupole where the electric potential is given by ψ(x,y,t) = (V/ro)*(x^2 + y^2)*Cos(Ωt). Where we are supposed to use the values V = 150 volts, ro (which is the distance from the center to one of the surface walls) = 3mm, and Ω = 500,000 Hz.

    My question is, is that potential the correct potential? It looks to me like the above potential gives units of Volts*meters instead of the correct units of Volts. Am I confused or should I say something to my professor? (I feel like the potential should be ψ(x,y,t) = (V/ro)*Sqrt(x^2 + y^2)*Cos(Ωt)

    I appreciate the help
  2. jcsd
  3. Feb 27, 2012 #2


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    Looks wrong to me. Ask your professor for clarification.
  4. Feb 27, 2012 #3
    thanks for responding vela
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