Power delivered by battery in simple RL circuit

Thread starter Taulant Sholla
Start date Apr 25, 2016
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Battery Circuit Power Rl circuit

AI Thread Summary

In a simple series LR circuit, the energy delivered by the battery can be calculated using the power equation P=IV and integrating over time. The user attempts to solve the integral ∫ Pdt by substituting P with IV, leading to the expression ∫ (V^2/R)(1-e^(-Rt/L))dt. However, they express confusion over the solution provided in the textbook, indicating a potential misunderstanding in their integration process. Ultimately, the user retracts their initial question, suggesting they found the answer elsewhere. The discussion highlights the complexities of calculating energy in RL circuits and the importance of correctly applying integration techniques.

Apr 25, 2016

Taulant Sholla

Homework Statement

For a simple series LR circuit, find the energy delivered to the circuit by the battery.

Homework Equations

I = (V/R)*(1-e^-Rt/L)
P=IV
E=∫Pdt

The Attempt at a Solution

Isn't ∫ Pdt = ∫ IVdt = ∫ (V²/R)*(1-e^-Rt/L)dt = (V²/R)(t + (L/R)e^-Rt/L) ?

The book provides the answer, via a sample problem, of:

What am I missing?

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Apr 25, 2016

Taulant Sholla

Oops - sorry - disregard the original post.

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