How to Calculate Power Radiated by a Sound Source?

AI Thread Summary
To calculate the power radiated by a sound source, the intensity of sound and the area of the circular opening are used. Given a loudspeaker with a diameter of 20 cm and an intensity of 0.2 milli watts/m^2, the area is calculated as approximately 0.0314 m^2. The power is then derived using the formula: Power = Intensity x Area, resulting in 6.28 x 10^(-6) watts. The discussion highlights confusion over basic physics principles, questioning whether the relationship between intensity and power is being correctly understood. Overall, the calculations presented are correct, but the underlying concepts are deemed trivial by some participants.
Amith2006
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Sir,
A loud speaker having a circular opening of diameter 20 cm is emitting sound waves uniformly. The intensity of sound at the opening is 0.2 milli watt/m^2. What is the power radiated by the source?
I solved it in the following way:
Intensity = power/Area
Here Area = (pi)R^2
= 3.14 x 0.01
= 0.0314 m^2
Power = 0.2 x 0.0314 milli watts
= 6.28 x 10^(-6) watts
Is it right?
 
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Sir,
Please respond.
 
Amith2006 said:
Sir,
Please respond.
Amith, No one is responding to this because it is trivial. You are saying:

A/B = x

And then asking:

Does A = Bx?

This is hardly advanced physics.

AM
 
I think what he is saying is:

Does A/B = x ? In other words, does A = bx ??
 
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