How Do Hairdryers Adjust Power Settings with Constant Resistance and Voltage?

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Hair dryers can achieve multiple power settings through a design that utilizes resistors connected in parallel, allowing for different configurations to produce varying power outputs. In the low setting, only one resistor is engaged, resulting in 600 watts, while both resistors are activated in the high setting, yielding 1200 watts. This setup demonstrates that resistance is not constant, as the total resistance decreases when both resistors are used, leading to increased current and power consumption. The discussion also touches on the potential for electronic controllers that may adjust motor speed alongside heating power. Understanding these principles clarifies how hair dryers manage to provide different heat levels effectively.
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A hair dryer hooked up to a DC power supply has 2 power settings.

One is 600 watts and the other is 1200 watts.

How is a hairsdryer able to have 2 power settings when resistance is constant and the voltage is constant?

Am I missing a valuable component inside a hairdryer that allows this to happen? What's going on?
 
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The implementations I've seen are that the heating element is split into 2 parts.
In one mode only one section is powered in the other both sections are powered.
So the resistance in this case is not constant.
 
so, with a higher resistance at constant voltage...the current must be lower. If current is lower at higher resistance, the power consumed is lower. so, at 600 watts setting, the hairdryer is connecting to the part that contains more resistance. IS THIS CORRECT?

it's a bit awkward because you would think that the higher resistance would produce a higher power setting.
 
casanova2528 said:
so, with a higher resistance at constant voltage...the current must be lower. If current is lower at higher resistance, the power consumed is lower. so, at 600 watts setting, the hairdryer is connecting to the part that contains more resistance. IS THIS CORRECT?

it's a bit awkward because you would think that the higher resistance would produce a higher power setting.

Or they're two resistors connected in parallel?
 
casanova2528 said:
A hair dryer hooked up to a DC power supply has 2 power settings.

One is 600 watts and the other is 1200 watts.

How is a hairsdryer able to have 2 power settings when resistance is constant and the voltage is constant?

Am I missing a valuable component inside a hairdryer that allows this to happen? What's going on?

What hair dryers are hooked up to a DC voltage source? That looks like a typo to me. Beyond that, the other replies are correct.
 
berkeman said:
What hair dryers are hooked up to a DC voltage source? That looks like a typo to me. Beyond that, the other replies are correct.

this is a hypothetical situation...of course, AC voltage at 60 hz and peak voltage of 170 V is standard in the usa...but just to understand how a hairdryer power setting is setup...DC current is used.
 
i'm not sure if that is correct...

look at your standard hairdryer with 2 power settings. the setting at higher power usually creates more heat for your hair drying purposes. the 600 watt setting should not create more heat, and the 1200 watt setting creates more heat. TRY IT YOURSELF...TURN ON A HAIRDRYER WITH 2 POWER SETTINGS...WHAT'S GOING ON?
 
MATLABdude said:
Or they're two resistors connected in parallel?

casanova2528 said:
i'm not sure if that is correct...

look at your standard hairdryer with 2 power settings. the setting at higher power usually creates more heat for your hair drying purposes. the 600 watt setting should not create more heat, and the 1200 watt setting creates more heat. TRY IT YOURSELF...TURN ON A HAIRDRYER WITH 2 POWER SETTINGS...WHAT'S GOING ON?

Let's assume you have two resistors, both of resistance R (say, 24 ohms). On the low setting, only one of these resistors is connected:
P=\frac{V^{2}}{R}=\frac{120^{2}}{24}=600 W

On the high setting, both of these resistors are connected in parallel, resulting in a total resistance of R/2 (in this example, 12 ohms). Consequently, the power consumed is:
P=\frac{V^{2}}{R}=\frac{120^{2}}{12}=1200 W

It's because they are connected in parallel (and not series) that you can twice the resistance (if you just added up the numbers, ignoring their connectivity) and twice the power.
 
oh...i haven't gotten to parallel and series resistors set ups.

so, if resistors are set up in parallel, you don't add the resistance like you add capacitance...is that right?
 
  • #10
casanova2528 said:
oh...i haven't gotten to parallel and series resistors set ups.

so, if resistors are set up in parallel, you don't add the resistance like you add capacitance...is that right?

:confused:How do you start connecting up capacitors before resistors?:confused:

But yes, you add them the opposite of how you add capacitances:
http://en.wikipedia.org/wiki/Series_and_parallel_circuits
 
  • #11
It could have a single element and an electronic (switched mode) power controller.

I seem to remember one which also altered the motor speed as well as the heating power.
 
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