Power Supply Output: Connecting + and - to Plates

AI Thread Summary
To create a capacitor using a power supply, connect the positive terminal to one plate and the negative terminal to the other, while ignoring the ground. The ground connection is unnecessary for this setup. Users are advised to check the resistance of the COM terminal, which is likely a common connection, using a digital multimeter (DMM). Understanding the power supply's function can be clarified by examining the connections and their purposes. This method ensures proper capacitor formation between the parallel plates.
anameel
Messages
3
Reaction score
0
I am trying to make a capacitor by connecting + and - to the electrodes between two parallel plates. There are + and - and Ground in the power supply which of these should I connect to the two plates and how does it work.


thanks
 
Physics news on Phys.org
Connect positive to one side and negative to the other. No ground. Check out

http://ocw.mit.edu/courses/physics/8-02-electricity-and-magnetism-spring-2002/video-lectures/lecture-7-capacitance-and-field-energy/
 
LostConjugate said:
Connect positive to one side and negative to the other. No ground. Check out

http://ocw.mit.edu/courses/physics/8-02-electricity-and-magnetism-spring-2002/video-lectures/lecture-7-capacitance-and-field-energy/


thanks
 
I am having a problem to understand how this power supply works. (attached)
photo.jpg



could anyone please explain to me how it works. I am confused with the ground part. Also, I do not know what COM is?
 
Ignore it.

You simply do not need it.

If you have a DMM check resistance from that terminal to the ground prong on the power plug. They may be connected.

I would guess that the Com terminal is just that, common. Again use your DMM to check resistance between the 2 com terminals.
 
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...

Similar threads

Back
Top