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I'm trying to use LOGs other than log base 10 and base e on my TI-86. Can I accomplish this like this?:
log base a of b = (log base 10 of b) / (log base 10 of a) ?
or is it:
log base a of b = (ln b) / (ln a) ?
Help needed ASAP. Thanks!
log base a of b = (log base 10 of b) / (log base 10 of a) ?
or is it:
log base a of b = (ln b) / (ln a) ?
Help needed ASAP. Thanks!