Predict sign of partial derivatives

In summary: Not the east. So if you are going from a more negative x to a less negative x (i.e. a to b), dT/dx < 0.
  • #1
fk378
367
0

Homework Statement


The temperature T at a location in the Northern Hemisphere depends on the longitude x, latitude y, and time t so we can write T=f(x,y,z); time is measured in hours from the beginning of January.

Honolulu has longitude 158 degrees W, and latitude 21 degrees N. Suppose that at 9:00 AM on January 1, the wind is blowing hot air to the northeast, so the air to the west and south is warm and the air to the north and east is cooler. Would you expect fx(158, 121,9), fy(158, 121,9), and ft(158, 121,9) to be positive or negative? Explain.

Homework Equations


dT/dx = change in temperature as longitude varies
dT/dy = change in temperature as latitude varies
dT/dt = change in temperature as time varies

The Attempt at a Solution


As longitude varies, the temperature in the north would get cooler, so would it be a negative partial derivative?

I'm not sure how to approach this.
 
Physics news on Phys.org
  • #2
fk378 said:

Homework Equations


dT/dx = change in temperature as longitude varies
dT/dy = change in temperature as latitude varies
dT/dt = change in temperature as time varies



The Attempt at a Solution


As longitude varies, the temperature in the north would get cooler, so would it be a negative partial derivative?

There is no special trick to partial derivatives: they still express rates of change of a function with respect to a change in an independent variable -- there is just more than one variable now.

The value of (North) latitude is increasing as you go north, while the temperature is falling. So you are correct that dT/dy < 0 . (I presume you meant 'latitude' in your question, since you mentioned the temperature 'in the north'.)

Be careful about dT/dx: what longitude is being used and which way does it increase? As for dT/dt, you need to consider how the air is moving and what will happen to the temperature at Honolulu as time passes...
 
Last edited:
  • #3
try to draw a graph of temperature

if
keeping y and z constant, and x goes from a (less positive x) to b (more positive x), and Temperature decreases, then dT/dx is?
 
  • #4
Crucial point is what dynamicsolo implied: x increases to the WEST.
 

1. What is the purpose of predicting the sign of partial derivatives?

The purpose of predicting the sign of partial derivatives is to determine the direction of change in a function with respect to one of its variables. This can help in understanding the behavior of the function and can be useful in optimization problems.

2. How do you predict the sign of partial derivatives?

To predict the sign of partial derivatives, you can use the first or second derivative test. The first derivative test involves finding the critical points of the function and analyzing the sign of the derivative at those points. The second derivative test involves finding the critical points and analyzing the sign of the second derivative at those points.

3. What does a positive sign of a partial derivative indicate?

A positive sign of a partial derivative indicates that the function is increasing in the direction of that variable. This means that as the value of the variable increases, the value of the function also increases.

4. What does a negative sign of a partial derivative indicate?

A negative sign of a partial derivative indicates that the function is decreasing in the direction of that variable. This means that as the value of the variable increases, the value of the function decreases.

5. Is predicting the sign of partial derivatives always accurate?

No, predicting the sign of partial derivatives is not always accurate. It is based on the assumption that the function is differentiable, which may not always be true. Additionally, the predicted sign may not hold true for all values of the variable, as there may be points of inflection or other critical points that can affect the behavior of the function.

Similar threads

  • Calculus and Beyond Homework Help
Replies
1
Views
997
  • Calculus
Replies
2
Views
2K
  • Calculus and Beyond Homework Help
Replies
2
Views
1K
Replies
4
Views
2K
Replies
1
Views
631
  • Calculus and Beyond Homework Help
Replies
2
Views
4K
  • Calculus and Beyond Homework Help
Replies
26
Views
3K
Replies
3
Views
2K
  • Calculus and Beyond Homework Help
Replies
1
Views
1K
Back
Top