Predicting the Spontaneity of 2BH3(g)->B2H6(g): Help Needed!

  • Thread starter Thread starter yolo123
  • Start date Start date
  • Tags Tags
    Spontaneity
AI Thread Summary
The discussion centers on the spontaneity of the reaction 2BH3(g) -> B2H6(g). Participants note that the change in entropy (DSsystem) is negative, but they require more information on the enthalpy change (DH) to determine spontaneity. There is uncertainty about whether the reaction is exothermic or endothermic, with suggestions that it may be exothermic due to the dimerization of borane. The conversation highlights the challenges of answering such questions in an exam setting without access to reference materials. Ultimately, the spontaneity of the reaction may depend on temperature and specific enthalpy values.
yolo123
Messages
63
Reaction score
0
2BH3(g)->B2H6(g)

Which is true?
a) Reaction is always spontaneous.
b) Reaction is always non-spontaneous.
c) Reaction is sometimes spontaneous sometimes not.
d) Reaction is endothermic.
e) Two of the above are true.


I know DSsystem is negative. But I would need more information on DH to say anything else. Please help me!
 
Physics news on Phys.org
yolo123 said:
2BH3(g)->B2H6(g)

Which is true?
a) Reaction is always spontaneous.
b) Reaction is always non-spontaneous.
c) Reaction is sometimes spontaneous sometimes not.
d) Reaction is endothermic.
e) Two of the above are true.


I know DSsystem is negative. But I would need more information on DH to say anything else. Please help me!

http://www.nist.gov/data/PDFfiles/jpcrd544.pdf
 
Last edited by a moderator:
Chestermiller, we cannot have access to these ressources in exams. We should do it without references. Can we say for sure that the reaction is exothermic since the reaction is a synthesis reaction?
 
yolo123 said:
Chestermiller, we cannot have access to these ressources in exams. We should do it without references. Can we say for sure that the reaction is exothermic since the reaction is a synthesis reaction?
Sorry. I can't help you on this, if that is the case. Please check with Borek who is very knowledgeable.

Chet
 
No idea, which is why I have not commented earlier. Perhaps the data were given in other parts of the test?
 
If this is asked in test, from my experience, you just have to consider that Borane, being electron deficient molecule, tried to remove the deficit by dimerizing (making bond). Hence you could say that the change in Enthalpy is negative. However, it is difficult to say about the spontaneity all by itself, except it can be below certain temperature.

Remember, if this is just a test, my reasoning is a valid flying guess (at least in the type of tests I gave during my college entrance preparations)
 
Thread 'Confusion regarding a chemical kinetics problem'
TL;DR Summary: cannot find out error in solution proposed. [![question with rate laws][1]][1] Now the rate law for the reaction (i.e reaction rate) can be written as: $$ R= k[N_2O_5] $$ my main question is, WHAT is this reaction equal to? what I mean here is, whether $$k[N_2O_5]= -d[N_2O_5]/dt$$ or is it $$k[N_2O_5]= -1/2 \frac{d}{dt} [N_2O_5] $$ ? The latter seems to be more apt, as the reaction rate must be -1/2 (disappearance rate of N2O5), which adheres to the stoichiometry of the...
I don't get how to argue it. i can prove: evolution is the ability to adapt, whether it's progression or regression from some point of view, so if evolution is not constant then animal generations couldn`t stay alive for a big amount of time because when climate is changing this generations die. but they dont. so evolution is constant. but its not an argument, right? how to fing arguments when i only prove it.. analytically, i guess it called that (this is indirectly related to biology, im...
Back
Top