Pressure Difference Between the Inside and Outside of a Balloon

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Discussion Overview

The discussion revolves around calculating the material strength required for a balloon to withstand pressure differences, specifically comparing scenarios of internal pressure versus external pressure. Participants explore the implications of different materials, including rubber and mylar, and consider applications beyond balloons, such as in astronaut space suits.

Discussion Character

  • Technical explanation, Conceptual clarification, Debate/contested

Main Points Raised

  • One participant inquires about calculating the material strength needed for a balloon under a pressure difference of 10 atm inside versus 1 atm outside, and also considers the scenario of a vacuum chamber.
  • Another participant provides a formula for biaxial tensile stress in a spherical balloon, questioning whether this applies to mylar balloons as well.
  • A subsequent participant expresses interest in the applicability of the equation to various materials, including rubber, mylar, steel, plastics, and glass, and mentions a specific interest in astronaut space suits.
  • One participant notes that if the material does not stretch significantly, a specific term in the equation simplifies to unity.
  • Another participant seeks clarification on the meaning of a symbol in the equation related to stress.
  • A later reply clarifies that the symbol represents stress and can be compared against the yield stress of different materials.

Areas of Agreement / Disagreement

Participants have not reached a consensus on the applicability of the equation to different materials or the implications of material properties on the calculations. Multiple views on the material considerations remain present.

Contextual Notes

The discussion includes assumptions about material behavior under stress and does not resolve the complexities of applying the equation across different materials or conditions.

Kyle Roode
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Hello all. I have a question about gasses and pressure: Is there a way to calculate how strong a material making up a balloon has to be to withstand a given pressure difference between the inside and outside?

In other words, if I have a balloon I need to fill to a pressure of 10atm inside vs 1atm outside the balloon, is there a way to calculate how strong the material needs to be to withstand this difference in pressure?

What if I took that same balloon and put it into a vacuum chamber (lowering from 1atm to say 0.1atm outside the balloon)?
 
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The biaxial tensile stress in the balloon rubber of a spherical balloon is given by $$\sigma=\frac{(\Delta p) r_0}{2h_0}\left(\frac{r}{r_0}\right)^3$$where ##r_0## and ##h_0## are the radius and material thickness when the internal pressure only slightly exceeds the external pressure and r is the balloon radius when the balloon is at full pressure. Is this what you were looking for? Or is this a mylar balloon?
 
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Thank you for the response. That equation is helpful for me.

What would change for the equation if it were mylar? I was really only using a balloon as an example. I am actually curious about using any material (be that rubber, mylar, steel, plastics, glass...). Does this equation work for any material?

It may be helpful to know my original thoughts before posting this were specifically in reference to an astronaught’s space suit. I thought maybe a balloon would just be a place to start.
 
Kyle Roode said:
Thank you for the response. That equation is helpful for me.

What would change for the equation if it were mylar? I was really only using a balloon as an example. I am actually curious about using any material (be that rubber, mylar, steel, plastics, glass...). Does this equation work for any material?

It may be helpful to know my original thoughts before posting this were specifically in reference to an astronaught’s space suit. I thought maybe a balloon would just be a place to start.
If the material comprising the balloon doesn't stretch significantly, then the term involving r/ro is unity.
 
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Thank you for taking the time to answer my question.

One last thing: what does the symbol on the left-side of the equation mean?
 
The symbol on the left stands for stress, the value of which can be compared against the yield stress of different materials
 

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