Pressure in Mouth: Calculate Using ρgh

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There was a question on a quiz I just took and I want to make sure I got it right.

Something like:
"A beaker filled with to [itex]2/3[/itex] its height with a fluid of density ρ = 1500kg / m3. You place a straw in the fluid such that the fluid in the straw is at a height equal to that of the fluid prior to having a straw put in (i.e., the height of the fluid is still [itex]2/3[/itex] of the max height). You suck the fluid in the straw up 25cm. What is the pressure in your mouth?"

After a good while of trying to overthink it (using Bernoulli's principle) I figured that it would just be ρgh = (1500kg / m3)(9.81m / s2)(0.25m). Is it right or wrong? It may very well be the difference between an A and a B so it'll just kill me to not know 'til I find out my grade Monday.
 
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haruspex said:
What is the pressure in your mouth when it is open?

Shouldn't it be atmospheric pressure?

haruspex said:
When you are holding the liquid up by sucking, is the pressure more or less, and by how much?

I would imagine there'd be more.

I suppose p = patm + ρgh should've been the answer then?
 
haruspex said:
Hmmm. So would it be less if you were to blow instead?

Nevermind I suppose it'd be the other way around. Fluid would be sucked in (as air would be) because the pressure in the mouth is less. So that leaves me at a complete loss as far as what the answer is concerned.

Would it be patm - ρgh? ρgh being the change in pressure necessary to bring up that fluid 25cm?
 
CWatters said:
Yes.

Provided the 25cm is measured from the new fluid level in the glass not the original level.

My teacher did say not to take change in original fluid level into account, but I gotcha. Thanks, I appreciate it.