Pressure in water and different liquid

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Scarlet_pat
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Homework Statement


consider the figures 1 and 2 which show two identical, rectangular wooden blocks

Weight of the block:



Homework Equations



Pressure = F/a
Pressure = Density x gravity x height



The Attempt at a Solution



The weight of the block,
i have tried to find the pressure of water of figure1

pressure = p g h = p = 1000 x 9.8 x 0.05 = 490 N/m^2

but i do not have any idea of what to do after.

thank you very much
 

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There is no need for finding pressure. Find the buoyant force
 


the buoyant force = V p g ...
the buoyant force = to the force exerted by the object.
therefore times the buoyant force by two, Because it is exact half submerged ?
 
Hi Scarlet_pat! :smile:

(have a rho: ρ :wink:)
Scarlet_pat said:
the buoyant force = V p g ...
the buoyant force = to the force exerted by the object.
therefore times the buoyant force by two, Because it is exact half submerged ?

Yes, but that's no way to prove it :redface:

you need to write an equation, weight + buoyant force = 0.

(btw, you could have used pressure … the upward force from the water is the pressure times the area of the base … but buoyant force is more sensible :wink:)
 


thank you very much for comfirming my answer :)
i was actually try to the method you have just suggested.
F= Pa = p g h * A

the the pressure there is always referring to Pressure of liquid right ?

however i think i have made a mistake ...
for F= V p g <-- the volume should be the volume of the object which submerged in the liquid right ?
 
Scarlet_pat said:
for F= V p g <-- the volume should be the volume of the object which submerged in the liquid right ?

(What happened to that ρ I gave you? :confused:)

I'm confused …

is ρ here the density of the block or of the water, and is this supposed to be the buoyant force or the weight?
 


lets just stick to the first equation ;)
F = V p g

and what I'm wondering is F = upthrust ,
V = volume of object submerged in liquid OR volume of the block?
p = density of liquid
g = acceleration due to gravity

am i right ?
 


ok thanks ... thank you. ill have to time the upthrust by 2, because the object is only half submerged ... right ?