Pressure of an ideal gas -- A Level Multiple Choice Problem

Thread starter maxelcat
Start date Dec 12, 2019
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A level Choice Gas Ideal gas Multiple Multiple choice Pressure

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SUMMARY

The discussion centers on a multiple-choice problem regarding the pressure of an ideal gas, specifically addressing the relationship between pressures in two connected chambers. The assertion made, $$\frac{P_x2V_y}{150}=\frac{P_yV_y}{300}$$, is identified as incorrect due to the misinterpretation of the connection between the chambers. The correct conclusion is that the pressures are equal, leading to the conclusion that $$P_x=P_y$$, thereby correcting the earlier factor of four error in the calculations.

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Understanding of ideal gas laws
Basic knowledge of pressure-volume relationships
Familiarity with mathematical manipulation of equations
Concept of connected gas chambers

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Students preparing for A Level physics exams, educators teaching thermodynamics, and anyone interested in mastering the principles of gas behavior in connected systems.

Dec 12, 2019

maxelcat

Homework Statement: Bit stuck on this... AQA question. I know I am doing something wrong but I can't see it

Two flasks X and Y are filled with an ideal gas and are connected by a tube of negligible volume compared to that of the flasks. The volume of X is twice the volume of Y.

X is held at a temperature of 150 K and Y is held at a temperature of 300 K

What is the ratio of mass in x / mass in y

Please can anyone help?

Thanks

Relevant Equations: (pV/ T)= constant and pV=n RT

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Dec 12, 2019

maxelcat

Sorry meant to say answer is c

Dec 12, 2019

jbriggs444

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As I understand your work, you start by asserting: $$\frac{P_x2V_y}{150}=\frac{P_yV_y}{300}$$Where does this assertion come from?

You then use the truth of that assertion to conclude that$$P_x=\frac{P_y}{4}$$But the fact that there is a tube connecting the two chambers indicates that in fact, ##P_x=P_y##.

Your factor of four error is right there.