Pressure required for air flow through nozzle

AI Thread Summary
To determine the maximum compression speed for a rectangular bladder with a 0.5" air port without rupturing it, the focus should be on the air flow rate through the orifice at 0.5 psi. The area of the bladder and the time required for air to escape through the port are critical factors in this calculation. Using a gauge between the outlet and the orifice can help measure the pressure accurately, though it may provide an under-reading. It's essential to prioritize the air flow rate over the bladder's integrity when calculating the necessary compression weight. For practical applications, flow charts and online resources can assist in finding relevant data.
John Treadstone
Messages
1
Reaction score
0
I need to know the maximum compression speed that can be applied to a rectangular bladder which has a open air port that will avoid rupturing the bladder. The bladder is 40" wide, 100" long, and 10" tall. The compression equipment is a large metal panel that is larger than the surface area of the bladder. The material inside the bladder is air. The port has an internal diameter of 0.50" and is a rigid material. The bladder has a maximum internal psi capacity of 0.5psi to avoid ruptures. Ignoring the flexing of the bladder material, is there a way to calculate this rate of compression that I could achieve while not rupturing the bladder? Thank you.
 
Physics news on Phys.org
Is this a real life situation, and is the port detachable from the bladder? You could merely install a gauge between the outlet and the .5" orifice to find your answer. Even if it's molded in you could attach a gauge and then another orifice, giving you something akin to a differential compression tester, but it would be inaccurate, probably under-reading.

If this a homework question you should post this on the Homework Forums.

Most of my experience as a tech with measured ports is their usage as limiting factors. So, from my perspective, you would be dealing with the area of the bladder, the time needed for the amount of air from the full bladder to flow through the orifice at .5 PSI (length of the orifice matters}, and I think you should be able to solve for the weight needed from there.

Don't look at how to keep the bladder from rupturing; solve for being able to get the air out, which is calculable easily. Then calculate the weight needed to do that.

If this is real world, you could have flow charts on hand. Or as they say on here a lot, 'Google is your friend.'

//edits for clarity//
 
Last edited:
I have recently been really interested in the derivation of Hamiltons Principle. On my research I found that with the term ##m \cdot \frac{d}{dt} (\frac{dr}{dt} \cdot \delta r) = 0## (1) one may derivate ##\delta \int (T - V) dt = 0## (2). The derivation itself I understood quiet good, but what I don't understand is where the equation (1) came from, because in my research it was just given and not derived from anywhere. Does anybody know where (1) comes from or why from it the...
Back
Top