- #1
Ryan26
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I am currently investigating pressure test safety with my current employer. Currently we test pressure vessels inside steel test containers, see attached pdf.
At the moment Boyles law is used to calculate the resultant pressure increase inside the steel container if the pressure vessel was to fail and suddenly release pressurised Nitrogen. However I don't believe this takes into account the volume of air that would be trapped and compressed inside the steel container. This means the actual volume the Nitrogen occupies is less than internal dimensions of the test container and there for the pressure inside after a vessel failure would be higher.
We use this (p1v1= p2v2, p(nitrogen 1kpsi) x v(volume of vessel) = p2 (?) x v(volume of test container).
What can I do to take into account the atmospheric pressure and volume of air already inside the test container to obtain a more accurate p2?
Thank you very much,
At the moment Boyles law is used to calculate the resultant pressure increase inside the steel container if the pressure vessel was to fail and suddenly release pressurised Nitrogen. However I don't believe this takes into account the volume of air that would be trapped and compressed inside the steel container. This means the actual volume the Nitrogen occupies is less than internal dimensions of the test container and there for the pressure inside after a vessel failure would be higher.
We use this (p1v1= p2v2, p(nitrogen 1kpsi) x v(volume of vessel) = p2 (?) x v(volume of test container).
What can I do to take into account the atmospheric pressure and volume of air already inside the test container to obtain a more accurate p2?
Thank you very much,