Greg Bernhardt said:
hmmm I just tested in here and preview worked for me
Yes, here. I mean, in a DM. I tested
Proof: If there is a prime number ##p## such that ##p\in\mathbb{Q}##, then we have an equation
$$
\sqrt{p} = \dfrac{r}{s}\quad (*),
$$
where we may assume that ##r,s## are coprime. Hence, ##p \cdot s^2=r^2.## Thus ##p## divides ##r,## say, ##r=q\cdot p.## Then ##r^2=q^2\cdot p^2## and ##s^2=q^2\cdot p.## This, however, implies that ##p## divides ##s## and ##r/s## wasn't coprime contradicting our assumption. This means that the equation ##(*)## does not exist and ##\sqrt{p}\not\in \mathbb{Q}.##
and didn't get a preview at all. (The first time prior to this thread yielded a preview except for
$$
\sqrt{p} = \dfrac{r}{s}\quad (*),
$$
which didn't render at all. A few refreshes later, I had ASCII.
Refresh works after posting, but not while typing.
