Prime Implicants of a Non-Coherent Fault Tree

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SUMMARY

The discussion focuses on the analysis of a non-coherent fault tree represented by the boolean function TOP(A, D, E) = A' D + D A' + A' E. The prime implicants identified are A' D, D A', and A' E, which are confirmed as minimal implicants that cannot be expanded further. Additionally, the prime implicant ED' is mentioned but not derived through De Morgan's laws. The conclusion is that the identified prime implicants are the only ones for this function since it is a sum of minterms.

PREREQUISITES
  • Understanding of non-coherent fault tree analysis
  • Familiarity with boolean algebra and prime implicants
  • Knowledge of De Morgan's laws
  • Basic concepts of fault tree analysis (FTA)
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  • Study the application of De Morgan's laws in boolean functions
  • Explore advanced techniques in fault tree analysis
  • Learn about minimal cover and prime implicant charts
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This discussion is beneficial for engineers, safety analysts, and reliability professionals involved in fault tree analysis and those seeking to deepen their understanding of boolean functions and prime implicants.

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I am stuck on some non-coherent fault tree analysis. I have a non-coherent fault tree for which the TOP event breaks down to TOP = AD' + DA' + A'E. These are (I think) some of the prime implicants of the fault tree. There is also another prime implicant ED'. I've been trying to work through it with De Morgan's laws but with no luck getting that final prime implicant (ED'). I've attached an image of the fault tree. Any ideas?
 

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So you have a boolean function:

$$TOP(A, D, E) = A \bar D + D \bar A + \bar A E$$

surreystudent said:
These are (I think) some of the prime implicants of the fault tree.

You would be correct. ##A \bar D, D \bar A,## and ##\bar A E## are prime implicants of the ##TOP## function because they are minimal implicants. We cannot expand the terms by removing literals because they would then become non-implicants. It is also worth noting these prime implicants cannot be covered by a more general implicant.

In fact, ##A \bar D, D \bar A,## and ##\bar A E## are the only prime implicants of the function because the function is a sum of minterms already.

What exactly are you trying to do here anyway? Are you trying to apply De-Morgan's laws to find different prime implicants?
 

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