Print ViewSimultaneous Measurements of Position and Velocity

[Sasa888]

Homework Statement

The x coordinate of an electron is measured with an uncertainty of 0.200 mm. What is v_x, the x component of the electron's velocity, if the minimum percentage uncertainty in a simultaneous measurement of v_x is 1.00 %? Use the following expression for the uncertainty principle:

(Delta x * Delta p_x )> or = h/2pi,

where Delta x is the uncertainty in the x coordinate of a particle, Delta p_x is the particle's uncertainty in the x component of momentum, and where h is Planck's constant.




My attempt:

delta p_x = h/(2pi*delta x)

delta p_x=m* delta v_x ??

i dnt know if i am allowed to do this.. also if it is allowed i don't know what to do next..

 

[borgwal]

So far so good! Now the other thing you have been given is that delta v_x is 1% of v_x.

 

[Sasa888]

Ok I am going to try it
Thanks a lot!