Probabilistic interpretation of wave function

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SUMMARY

The discussion focuses on determining the normalization constant A for the wave function \(\Psi(x) = A \sin(\frac{\pi x}{L})\) of a particle confined between rigid walls at x=0 and x=L. The integral \(\int_0^L \Psi^* \Psi \, dx\) must equal 1 to satisfy the probability interpretation of the wave function. By substituting \(\Psi^*\) with \(A \sin(\frac{\pi x}{L})\) and evaluating the integral, the value of A can be calculated. The integral evaluates to \(\frac{A^2 L}{2}\), leading to the conclusion that \(A = \sqrt{\frac{2}{L}}\).

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Homework Statement


a particle moving in one dimension between rigid walls separated by a distance L has the wave function \Psi(x)=Asin(\Pix/L), since the particle must remain between the walls, what must be the value of A?


Homework Equations





The Attempt at a Solution



Ok so I'm thinking that since the particle has to be between x=0 and x=1, i should set the probability function = to one for these limits on the integral. I'm really confused on how to do that though
 
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What must the following integral be equal to according to the probability interpretation of the wave function?

\int_0^L\Psi^*\Psi dx=?
 
1? to get psi* what do i do?

thanks
 
The star means complex conjugate: replaces all is with -is. In your case, \psi^* = A^* sin(\pi x / L), but you can takeA to be real, making \psi = \psi^*.
 
okay, thanks a lot
 
Yes, that integral is equal to 1. You now, need to evaluate that and figure out what A must be for that expression to be true.

(I have been busy today and I see I'm a little late to respond. I hope you were able to figure it out.)
 

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