Probabilities of A & B Occurrences in S

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The discussion revolves around calculating specific probabilities related to two events, A and B, within a sample space S, given their probabilities: P(A) = 0.7, P(B) = 0.6, and P(A ∩ B) = 0.4. Participants seek clarification on how to determine the probabilities of A occurring without B, exactly one of the events occurring, and neither event occurring. The confusion stems from the terminology used in the problem, particularly regarding the notation for probabilities. The correct approach involves using the formula P(A and not B) as P(A ∩ B'), indicating the need to account for the intersection of A and the complement of B. Understanding these concepts is essential for solving the homework problem effectively.
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Homework Statement


Suppose that A and B are two events of a sample space S such that P(A) = 0.7, P(B) = 0.6 and P(AinterceptB) = 0.4.
What are the probabilities of the following:
1. A occurs and B does now
2. Exactly one of the two events occurs
3. Neither event occurs.

I have tried this but the issue I am having is that I'm confused by the wording. We didn't really do anything like this in class, so I have no examples which coincide. Any help?

Thank you!
 
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P(A/B)= p(AnB)/P(B) which is the probability that B occurs given that A has already occured
to find the Probabilities...write out the the probability that you have to find...e.g P(A or B occurring) etc...
 
Hey

Sorry, I meant, "A occurs but B does not"... Would that simply be P(A)?
 
If P(A) means the probability that A occurs then for A to occur and B not to occur

then you'd want P(AnB')
 
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