Probability Density Function, prove it

AI Thread Summary
To prove that the function 1/x^2 is a probability density function (PDF) for x > 0, it must satisfy two conditions: the integral of the function over its domain must equal 1, and the function must be non-negative for all x. The integral of 1/x^2 from 1 to infinity is evaluated as -1/x, which approaches 1 as x approaches infinity. There is some confusion regarding the limits of integration, with a suggestion that the lower limit might need to be 1 instead of 0. Clarification on the correct limits is necessary to confirm that the function meets the criteria for being a PDF.
randy27
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Homework Statement


This is my 1st post here, so I will do my best. The following question is part of a number of probability density functions that I have to prove. Once I have the hang of this I should be good for the rest, here is the question:

Prove that the following functions are probability density functions:

1/x^2 , x>0

Homework Equations





The Attempt at a Solution



As I understand to prove a probability density function it must satisfy

1. integral of f(x)dx=1
and
2. must not be negative f(x) for all x


I integrate the function of 1/x^2 which is -1/x but I find it tricky to explain myself on how f(x)dx=1


I would be greatfull on pointers on how to prove that the functions is a PDF in a clear manner.
 
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You probably would have gotten a response quicker, but you posted this in the pre-calculus forum...

As I understand it, the integral needs to be = 1. (And, all values of f(x) > 0 which is your point 2.) However, I'm having trouble getting one when I integrate the function. Are you sure it's supposed to be x>0, and not x>1? Evaluating the improper integral from 1 to infinity =1 (unless I blundered somewhere; I did it really quick)
 
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