Probability - Exponential Function Question

Click For Summary

Homework Help Overview

The problem involves a Poisson process related to a species of mollusk, where the goal is to analyze the distance from a sensor to the nearest mollusk. The discussion centers around deriving the cumulative distribution function (c.d.f.) and probability density function (p.d.f.) of the distance variable Y, as well as computing the expected value E(Y).

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to derive the p.d.f. from the c.d.f. and compute the expected value using integration techniques, while expressing uncertainty about their approach and the use of the gamma function.

Discussion Status

Some participants provide feedback on the original poster's calculations, questioning specific steps taken in the integration process. The original poster indicates they have resolved their issue, suggesting a productive direction has been reached.

Contextual Notes

The original poster notes a specific value for gamma(4/3) and expresses concern about the correctness of their integration method, indicating potential confusion regarding the application of the gamma function in their calculations.

tokuroka
Messages
5
Reaction score
0

Homework Statement


A particular species of mollusk is distributed according to a Poisson process with an unknown density of lambda per cubic meter of water. A sensor is constructed that can detect these species that are within 4 m, and n readings are collected over a year to try and measure lambda. These readings are independent, and so the number of readings that detect a mollusk has the distribution X~Bi(n,p) for some unknown value of p.

p is estimated to be approximately 0.7.

Problem: Let Y be the distance from the sensor to the nearest mollusk.
Show that the c.d.f. of Y is of the form
F(y) = 1- e-(lambda)(4/3pi y3 if y >0.

b) Find the p.d.f. of Y and use it to compute E(Y).

Homework Equations


gamma(4/3) = 0.8929795

The Attempt at a Solution


I'm not so much worried about part a), but I tried part b) and I'm getting nowhere. I took the derivative of F(y) to get f(y) (the p.d.f) and got f(y) = 4pi(lambda) y^2(e-(lambda)(4/3 pi*y3, and then for E(Y), I multiplied that by y and took the integral from 0 to infinity of that. I read in my textbook that for the basic proof of expected value, you're supposed to make a substitution for theta = 1/lambda, and then substitute more values to make this integral look like the gamma function. So I substituted x = 4pi/3theta y^3 (to make the power of e = -x) and then what I am left with after simplifying is... the integral from 0 to infinity of e^-x dx... I'm pretty sure that's wrong though... since the problem tells me I should be using the gamma function of 4/3 for something.. Can anyone help me with this? Thanks.
 
Physics news on Phys.org
Did you write dy in terms of dx?
 
yeah I did.. then everything canceled out.
 
Sounds like you didn't multiply by y then. You calculated E(1), not E(y).
 
Ah, okay, I solved it now. Thanks.
 

Similar threads

Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 27 ·
Replies
27
Views
2K
Replies
3
Views
2K
Replies
8
Views
2K
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
11
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K