Probability Function Homework: Solving Parts (d), (e) & (f)

AI Thread Summary
To solve parts (d), (e), and (f) of the probability function homework, the constant k is determined to be 0.25, ensuring the total probability sums to 1. For part (d), it is established that P(X1 + X2 = 5) equals 0 due to the maximum possible sum of X1 and X2 being 4. In part (e), the complete probability function for X1 + X2 can be derived by convolving the individual probability functions of X1 and X2. Finally, part (f) requires calculating the probability P(1.3 < X1 + X2 < 3.2), which involves evaluating the probabilities for the relevant sums. This structured approach facilitates understanding the behavior of the random variable X and its combinations.
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Homework Statement


Hi
I am trying to solve the d, e and f parts of this problem

The discrete random variable X has probability function
where k is a positive constant.

P(X = x) ={k(2 – x), x = 0, 1, 2,
k(x – 2), x = 3,
0, otherwise,

(a) Show that k = 0.25.
(b) Find E(X) and show that E(X 2) = 2.5.
(c) Find Var(3X – 2).
Two independent observations X1 and X2 are made of X.
(d) Show that P(X1 + X2 = 5) = 0.
(e) Find the complete probability function for X1 + X2.
(f) Find P(1.3 < X1 + X2 < 3.2).

Not sure how to begin. Please help. The exam is tomorrow.



Homework Equations





The Attempt at a Solution

 
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For (a), what must be the answer if you sum P(X = x) over x = 0, 1, 2, 3?
 
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