Probability integration question

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The discussion revolves around calculating the probability P(X + Y > 1/2) for the joint density function f(x,y) = 1/y, valid for 0<x<y<1. Participants express confusion about the integration process, particularly regarding the limits and handling the natural logarithm of zero during integration. It is suggested to visualize the problem by graphing the line X + Y = 1/2 to determine the appropriate area for integration, considering the constraints of X < Y. Clarification is provided that the limit of y*ln(y) as y approaches zero is well-defined, which can assist in resolving integration issues. Overall, a diagram and careful attention to the integration limits are emphasized as crucial for solving the problem.
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Homework Statement



Let X denote the diameter of an armored electric cable and Y denote the diameter of the ceramic mold that makes the cable. Both X and Y are scaled so that they range between 0 and 1 . Suppose that X and Y have the joint density

f(x,y) = 1/y, 0<x<y<1
f(x,y) = 0, elsewhere

Find P(X + Y > 1/2)

Homework Equations





The Attempt at a Solution


Do not I just need to integrate 1/y from x to 1 with dx then from there integrate one more time with from 0 to 1/2 with dy ?

I am really confused with this question because if we integrate 1/y we get ln (y) and if we integrate one more time, we get y *(ln (y) - 1) but we cannot have ln (0).

Some please help me. This question is bothering me for the whole day.
BTW: I am sorry that I do not know how to put the integration symbol yet.

 
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It would probably be helpful to draw a diagram so that you can see the area where you need to integrate. You are looking for X+Y>1/2. Graph the line X+Y=1/2. This is the boundary of the constraint, and on one side of the line it holds, on the other it fails. Also, the function is nonzero only for X<Y, so this is another constraint on the area of integration. If you draw a picture, it should be clear what region to integrate in and how to set the limits.

As far as your second point about ln(y) for y=0, remember that it is y*ln(y). The limit has a definite value. (hint: L'Hopital's rule)

And about drawing integrals, hit the quote button to see how I did this:
\int_{x=0}^{x=1}f(x)dx
 

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