What Is the Defective Rivet Probability for Aircraft Seams?

AI Thread Summary
The discussion centers on calculating the probability of defective rivets in aircraft seams, specifically addressing scenarios where 20% and 10% of seams require reworking. It is suggested that if 20% of seams need reworking, the probability of a defective rivet is 1/25. For the second scenario, participants explore how to determine the necessary probability of a defective rivet to limit reworking to 10%. The conversation indicates a connection to binomial distribution concepts in solving these probability questions. Understanding these probabilities is crucial for maintaining aircraft safety and efficiency.
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An aircraft requires 25 rivets. The seam will have to be reworked if any of these rivets is defective. Suppose rivets are defective independently of one another, each with same probability.

(a) If 20 \% of all seams need reworking, what is the probability that a rivet is defective?

So this is equaled to \frac{1}{25}?


(b) How small should the probability of a defective rivet be to ensure that only 10 \% of all seams need reworking?
 
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Have you learned about binomial distribution yet?
 
figured it out, thanks.
 
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