Probability of 2 Defective Laptops Among 6 Purchased

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Homework Help Overview

The problem involves determining the probability of selecting exactly 2 defective laptops from a total of 6 purchased laptops, given a set of 10 laptops that includes an equal number of defective and non-defective units.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the independence of probabilities related to defective laptops and question the perspective from which the problem is approached. There are inquiries about the combinatorial aspects of selecting defective and non-defective laptops.

Discussion Status

The discussion is active, with participants exploring different interpretations of the problem and offering guidance to help the original poster clarify their understanding. Some participants note similarities in the probabilities of different arrangements of laptops.

Contextual Notes

There is a focus on the definitions and assumptions related to probability in the context of the problem, as well as the constraints of the sample space defined by the number of good and defective laptops.

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Homework Statement


Among 10 laptop computers, five are good and five have defects. Unaware of this, a
customer buys 6 laptops

What is the probability of exactly 2 defective laptops among them?

Homework Equations

The Attempt at a Solution


I'm having a hard time looking at this problem from the definitions in my book.

It seems to me that P(2/6 chosen laptops are defective) is not independent of P(5/10 laptops are defective),
but P(5/10 laptops are defective) is independent of P(2/6) chosen laptops, which would be impossible. This implies that I am looking at this problem from the wrong perspective

also it seems to me, that 1/6 of the chosen laptops, should be defective with probability .5
 
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How many ways of picking 2 defective and 4 working laptops from the 10? How many ways to pick 6 laptops regardless of defective status.
 
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r0bHadz said:

Homework Statement


Among 10 laptop computers, five are good and five have defects. Unaware of this, a
customer buys 6 laptops

What is the probability of exactly 2 defective laptops among them?

Homework Equations

The Attempt at a Solution


I'm having a hard time looking at this problem from the definitions in my book.

It seems to me that P(2/6 chosen laptops are defective) is not independent of P(5/10 laptops are defective),
but P(5/10 laptops are defective) is independent of P(2/6) chosen laptops, which would be impossible. This implies that I am looking at this problem from the wrong perspective

also it seems to me, that 1/6 of the chosen laptops, should be defective with probability .5

The sample-space consists of all strings of 6 letters "G" and "B" with at most 5 "B"s or 5 "G"s. So, a string such as GGBGGG means that his first two items are good, the third is bad, and the remaining three are good, while BBBBBG means the first 5 are bad and the 6th is good, etc. Remember, these are chosen from a set of 5 "G"s and 5 "B"s.

The event E you are interested in is the collection of such strings containing exactly 2 "B"s.

Look at some of these strings: (i) what is P(BBGGGG)? (ii) what is P(GGGGBB)? (iii) what is P(GGBGGB)?

What do you notice about these three probabilities?
 
Ray Vickson said:
The sample-space consists of all strings of 6 letters "G" and "B" with at most 5 "B"s or 5 "G"s. So, a string such as GGBGGG means that his first two items are good, the third is bad, and the remaining three are good, while BBBBBG means the first 5 are bad and the 6th is good, etc. Remember, these are chosen from a set of 5 "G"s and 5 "B"s.

The event E you are interested in is the collection of such strings containing exactly 2 "B"s.

Look at some of these strings: (i) what is P(BBGGGG)? (ii) what is P(GGGGBB)? (iii) what is P(GGBGGB)?

What do you notice about these three probabilities?
I am not the OP but arent these propabilities all the same?
 
Leo Consoli said:
I am not the OP but arent these propabilities all the same?
Yes, indeed, and realization of that fact goes a long way towards solving the problem. I was attempting to help the OP find the solution himself, instead of handing him a completer answer.
 

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