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CatastrophicF
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The windshield of a car has a width of 1067mm and a height of 889mm. The windshield also has a crack with a length of 305mm and a height of 1mm. What is the probability of a rock, with a random trajectory and a measurement of 1mmx1mm, hitting the windshield strikes directly in the center of the crack anywhere along its length?
Am I correct to calculate...?
Possible contact area of the windshield = 948,563mm^2
Possible contact area of the crack = 305mm^2
Probabilty of the rock striking the crack directly in the center of the crack anywhere along its length = 1/948,563(1/305) = 1/289,311,715
...or is it simply 1/948,563 and please explain why the former or the latter is correct
Am I correct to calculate...?
Possible contact area of the windshield = 948,563mm^2
Possible contact area of the crack = 305mm^2
Probabilty of the rock striking the crack directly in the center of the crack anywhere along its length = 1/948,563(1/305) = 1/289,311,715
...or is it simply 1/948,563 and please explain why the former or the latter is correct
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