- #1
IniquiTrance
- 190
- 0
In a group of 23 people, the probability that any 2 people share a birthday is:
1 - [tex]\frac{365!}{342!365^{23}}[/tex]
Why can't I just do the following?
[tex](23\mathbf{C}2)(\frac{1}{365})[/tex]
Thanks!
1 - [tex]\frac{365!}{342!365^{23}}[/tex]
Why can't I just do the following?
[tex](23\mathbf{C}2)(\frac{1}{365})[/tex]
Thanks!
Last edited: