Plotting Points on Normal Probability Paper: Tips & Tricks

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The discussion revolves around confusion regarding plotting points on normal probability paper. Participants emphasize the need to order the data before plotting. There is uncertainty about using the formula (i-0.5)/n for determining Z-scores and whether it applies to the current context. Questions arise about calculating mean and standard deviation from the graph itself, leading to further confusion about the purpose of the graph. Clarification is sought on the specific graph being referenced and the overall plotting methodology.
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Jus some confusion over plotting points on normal probability paper..

1. Order the data
2. Do we do (i-0.5)/n where i=no. of observation and n= no. of samples?
believe can't use Z(i)= (X(i)- Mean)/ stand. dev. as i need to find both mean and std. dev from the graph...
What is the graph plotted for...i mean i have X(i) Vs Z(i) but seem a bit in circles.

can anybody please let me know?thanks
 
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axnman said:
Jus some confusion over plotting points on normal probability paper..

1. Order the data
Okay, that should be easy.

2. Do we do (i-0.5)/n where i=no. of observation and n= no. of samples?
Do that for WHAT? I have no idea what you are taking about here.

believe can't use Z(i)= (X(i)- Mean)/ stand. dev. as i need to find both mean and std. dev from the graph...[\quote]
Use it for WHAT?

What is the graph plotted for...i mean i have X(i) Vs Z(i) but seem a bit in circles.

can anybody please let me know?thanks
What graph are you talking about? You don't actually state what your problem is!
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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