Probability Problem: 2 Ticket Draw, What's the Odds?

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The discussion centers on calculating the probability that the second ticket drawn from a box is greater than the first, with the formula presented as (1-1/n)/2. Participants debate the accuracy of this formula, particularly when n equals 2, and highlight that the probabilities of the first and second tickets being larger are equal. Clarification is sought on the implications of sampling with replacement versus without replacement, with the latter yielding a probability of 1/2. The conversation emphasizes the need for a deeper understanding of probability concepts and their applications in different sampling scenarios. Overall, the thread illustrates the complexities of probability calculations in drawing scenarios.
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A box contains tickets marked 1,2,...,n. Two tickets are drawn at random from the box. What is the probability the second number drawn is bigger than the first number drawn?
The answer shown is (1-1/n)/2. But... how?

Thanks in advance!
 
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What happens when n = 2?
 
Tide's point is that the "answer shown" is WRONG. It shouldn't take a whole lot of thought to see that the probability that "the second number drawn is bigger than the first number" is exactly the same as the probability that "the first number drawn is bigger than the second number.
 
Just out of curiosity, where did you get that formula?
 
Sorry to all, forgot to mention that this is "sampling with replacement". So, by using HallsofIvy's hint, I know how to derive it now. Thanks! And just curious, the answer for without replacement is 1/2?

HallsofIvy, can you give more explanation on "the second number drawn is bigger than the first number" is exactly the same as the probability that "the first number drawn is bigger than the second number"? they sound more like compliments to me with one higher and one lower probability...
 
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