Probability Question - Urn problem

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The discussion revolves around calculating the probability of drawing exactly 2 white balls from an urn containing 4 white and 4 black balls. A participant initially attempts to use a specific formula but realizes it is incorrect due to misunderstanding the changing probabilities after each draw. It is clarified that the probability of drawing a white ball is not consistently 1/2, as the composition of the urn changes with each selection. The importance of accurately describing the sample space and considering the sequence of selections is emphasized. The conversation highlights the need for a correct approach to probability in this scenario.
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Homework Statement



An urn contains 4 white and 4 black balls. We randomly choose 4 balls. IF 2 of them are white and 2 are black, we stop. If not, we replace the balls in the urn and again randomly select 4 balls. this continues until exactly 2 of the 4 chosen are white. What is the probability that we shall make exactly n selections.

Homework Equations





The Attempt at a Solution



I don't see why I can't find the probability of drawing exactly 2 white balls using this method.

(4C2)(4/8)^2(1-4/8)^2
where 4C2 is 4 choose 2

apparently this is wrong but I don't see why. Thanks for any help that you can provide.
 
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GreenPrint said:

Homework Statement



An urn contains 4 white and 4 black balls. We randomly choose 4 balls. IF 2 of them are white and 2 are black, we stop. If not, we replace the balls in the urn and again randomly select 4 balls. this continues until exactly 2 of the 4 chosen are white. What is the probability that we shall make exactly n selections.

Homework Equations





The Attempt at a Solution



I don't see why I can't find the probability of drawing exactly 2 white balls using this method.

(4C2)(4/8)^2(1-4/8)^2
where 4C2 is 4 choose 2

apparently this is wrong but I don't see why. Thanks for any help that you can provide.

Well, why do you think it's right? The probability of choosing a white ball is only 1/2 the first time you choose a ball. It's not always 1/2, is it?
 
oh i guess i always assumed you pick the things simultaneously as that's what I've been doing throughout the course so i guess this assumption is wrong?
 
GreenPrint said:
oh i guess i always assumed you pick the things simultaneously as that's what I've been doing throughout the course so i guess this assumption is wrong?

If you pick a white ball first that means there are 3 whites left and 4 blacks. The odds of picking a second white or a black aren't 1/2 anymore. So yes, it's wrong.
 
I think it is always useful to describe the sample space: you can succeed the 1st, or the 2nd time, etc.

EDIT: I mean, you can select the two balls in the first trial, or, if you don't, then at the second trial, etc.
 
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