Hi, i have this question A bag contains 5 red balls, 10 blue balls and 15 green balls. Three balls are drawn from the bag one after another without replacement. The event R1 , R2 , B2 and G3 are defined as follows. R1 - represents the event the first ball drawn is red. R2 - represents the event the second ball drawn is red. B2 - represents the event the second ball drawn is blue. G3 - represents the event the third ball drawn is green. Find a) i) P(R1 [tex]\cap[/tex] R2) for this , i drew a tree diagram, for it to be red for the first ball, it has to be 5/30 and for the second to be red it has to be 4/29 thus multiplying them both would give me the answer which is 2/87. ii) P(R1 [tex]\cup[/tex] R2) for this i thought of P(R1) + P (R2) - P(R1 [tex]\cap[/tex] R2) would solve the problem but the answer is incorrect and later i see, i don't really know what's the probability of R2 because it could be 5/29 or 4/29. Please help.