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## Homework Statement

A die is based so that the numbers 5 & 6 appear 3 times more often than the numbers 2 , 3 & 4. Calculate;

i)The probability that a two is thrown.

ii)The probability that two consecutive throws are > or equal to 10.

## The Attempt at a Solution

Well I wasn't sure how to go about this so i imagined all of the outcomes;

5 5 5 6 6 6 2 3 4 , satisfies the criteria meaning a 2 would be 1/9, however i have a feeling that that's nonsense...:S

Then for ii) Combo's are 46 64 65 56 55 66 so (4 * 1/9) + (2 * (3/81) = (36/81+6/81) = (42/81)?

I don't know how to go about these questions, sorry for bugging everyone >.<