Probability when seleting balls from an urn

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The problem involves calculating the probability of drawing 4 red balls from a total of 300 balls, of which 30 are red. The initial probability of drawing one red ball is 30/300, and subsequent probabilities depend on previous draws, resulting in 29/299, 28/298, and 27/297 for the next three draws. The correct approach for dependent events is to multiply the probabilities of each event occurring sequentially. Thus, the final probability of drawing all red balls is calculated as 30/300 * 29/299 * 28/298 * 27/297. This method accurately reflects the dependency of each draw on the previous one.
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Homework Statement



There is total of 300 balls in the basket, 30 of them is red (rest is white). If we picked up, randomly, 4 balls, what is the probabilty that all of them is red ?


2. The attempt at a solution

For one picked ball, probability that it's red is 30/300 = 1/10.
If picked ball is red, probabilty for next ball is 29/299,and so on, 28/298, 27/297.

Is that correct ? And, what next ?
 
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dperkovic said:

Homework Statement



There is total of 300 balls in the basket, 30 of them is red (rest is white). If we picked up, randomly, 4 balls, what is the probabilty that all of them is red ?


2. The attempt at a solution

For one picked ball, probability that it's red is 30/300 = 1/10.
If picked ball is red, probabilty for next ball is 29/299,and so on, 28/298, 27/297.

Is that correct ? And, what next ?


Yup, that's right so far.
In probability, what is the relationship with "And" events? :wink:
 


Maybe_Memorie said:
Yup, that's right so far.
In probability, what is the relationship with "And" events? :wink:

P(A and B) = P(A) x P(B) ?
 


dperkovic said:
P(A and B) = P(A) x P(B) ?

P(A and B) = P(A) x P(B after A) is correct,because this is depended events, is that true ?

If it is, the solution would be: 30/300 * 29/299 * 28/298 * 27/297.
 


Exactly. :smile:
 
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