Problem from Eisberg: Blackbody Radiation

raghav
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Homework Statement


In case of Cavity Radiation(Blackbody radiation) let \rho_{T}(\nu)d\nu denote the energy density of radiation having frequency in the interval \nu and \nu + d\nu.
Then we need to show that \frac{\int_{0}^{\lambda_{max}} \rho_{T}(\nu)d\nu}{\int_{0}^{\infty} \rho_{T}(\nu)d\nu} \approx \frac{1}{4}
where \lambda_{max} is the wavelength at which the radiation is most intense.



Homework Equations


The obvious rela\evant equation is
\rho_{T}(\nu)d\nu = \frac{8\pi h\nu^{3}}{c^{3}}\cdot \frac{d\nu}{e^{\frac{h\nu}{kT}}-1} . But the problem is the integration part. Can some one please help me with that?


The Attempt at a Solution

 
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OK, so:

\int \nu ^3 \cdot (e^{\frac{h\nu}{k_b T}}-1)^{-1} \cdot \delta \nu

Is the equation you need to solve, so you can use:

\int A \delta B = AB - \int B \delta A

(from the differentiation product rule). There's a start. Let me know if it helped.

Sam :smile:
 
Oops, and you'll probably need this standard integral:

\int_0^{\infty} \frac{x^3}{e^x -1}\delta x = \frac{\pi^4}{15}

Sam :smile:
 
BerryBoy said:
Oops, and you'll probably need this standard integral:

\int_0^{\infty} \frac{x^3}{e^x -1}\delta x = \frac{\pi^4}{15}

Sam :smile:

Yes i could evaluate the denominator using the standard integral u have mentioned, however the Numerator is creating trouble. I have also tried a parts argument, doesn't seem to be taking me any where :cry:
Some1 please help asap
 
I can't do this without some assumptions, have you stated the WHOLE question from the start?

Sam
 
Yes I have indeed given all the necessary details the problem demands. Essentially my doubt boils down to evaluating the integral
\int_{0}^{a} \frac{t^{3}}{e^{t}-1}dt ; a being some constant.
 
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