Problem sheet double integration

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SUMMARY

The discussion focuses on solving the double integral \(\int\int x^3(x^2+y^2) \, dy \, dx\) with specified limits for \(x\) from -4 to 2 and \(y\) from 0 to 5. The initial calculation yielded an incorrect result of -17426 2/3, while using Maple software provided a correct answer of -5860. The correct approach involves expanding the integrand to \(\int\int (x^5 + x^3y^2) \, dy \, dx\), integrating with respect to \(y\) first, and then \(x\), ensuring to account for the limits properly.

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Homework Statement



[tex]\int\int x^3(x^2+y^2)[/tex] dy dx limts of x between 2 and -4 and y limits between 5 and 0

Homework Equations





The Attempt at a Solution



i get an answer -17426 2/3 which doesn't seem right

plugged the formula into maple and has given me an answer of -5860.

my first step was to expand the brackets.

to get [tex]\int\int x^5 + x^3y^2[/tex] then integrate with respect to dy. put the limits of y in as 5 and 0.

[tex]\int 5x^5 + (125x^3/3)[/tex]
then integrate with respect to x and again put the limits in.
 
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I agree with Maple. I also agree with your x integration. Except I would put a minus sign in front because I integrated with a lower y limit of 5 and an upper y limit of 0. Is that what you meant? You'll have to show more intermediate results to be able to tell what you are doing wrong.
 

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