I am having problems understanding how a resistor resists or limits current flow (or electron flow). http://img714.imageshack.us/img714/5595/currentquestionimage.jpg [Broken] In circuit 1, if I understand correctly the current at Point 1, Point 2 and Point 3 are all the same – that is if you measure the current at each of these three points you will get the same measurement. Now to circuit number 2. I got this circuit from Scherz, Paul. (2000). Practical electronics for inventors. McGraw-Hill/TAB Electronics. Page 132 The caption that goes with the circuit is the following: This circuit will supply a steady output voltage equal to the sum of the forward-biasing voltages of the diodes. For example, if D1, D2 and D3 are silicon diodes, the voltage drop across each one will be 0.6V; the voltage drop across all three is then 1.8 V. This means that the voltage applied to the load (Vout) will remain at 1.8V. R1 is desinged to prevent the diodes from “frying” if the resistance of the load gets very large or the load is removed. Now my question is how does the resistor prevent the diodes from “frying” (or breaking down)? If Rload is removed from the circuit, I am under the impression that if you were to measure the current at Point 1, Point 2, Point 3, Point 4 and Point 5 that you will get the same measurement for current at each of these points. If this is so, how is the resistor preventing the diodes from frying?