Problem with Dynamics H.E.L.P please

  • Thread starter Thread starter Azeri
  • Start date Start date
  • Tags Tags
    Dynamics
AI Thread Summary
The tension in the rope is 40N when two boys pull it in opposite directions with equal forces of 40N. Each half of the rope is in equilibrium, meaning the forces acting on it balance out. According to Newton's First Law of Motion, the net force on the rope is 0N, indicating it is not accelerating. Therefore, the tension in the rope matches the applied forces. This scenario illustrates the principles of equilibrium and force balance in dynamics.
Azeri
Messages
19
Reaction score
0
"What is the tension of the rope if 2 boys pull it in opposite directions with equal forces of 40N?"

I guess it is 40N but not sure why.

THX for help.
 
Physics news on Phys.org
Hint:
Every piece of the rope is also in equilibrium, (not just the WHOLE rope)!
So, look at the half-rope with one boy at one end.
The half-rope is in equilibrium, hence, the rest of the rope must act upon it with a tension equal to...?
 


Yes, the tension of the rope would be 40N in this scenario. This is because when two equal forces are applied in opposite directions, the net force on the rope is 0N. According to Newton's First Law of Motion, an object at rest will stay at rest or an object in motion will continue to move at a constant velocity unless acted upon by a net external force. Since the rope is not accelerating, the net force on it must be 0N. Therefore, the tension in the rope must be equal to the forces applied, which in this case is 40N on each side. I hope this helps!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top