Problem with gravitation field perpendicular vector.

[Abdu Ewais]

since it is known that $\vec{A_\perp} = -{mG \over R^2}$ why did the professor write it as $\vec{A_\perp} = {- R G \rho \over 3}$ for perfect sphere with perfect mass distribution ? Shouldn't it be $\vec{A_\perp} = -{4 \over 3} \pi R G \rho$? I need help thanks.

 

[Doc Al]

If I understand your question, shouldn't that be a 4/3 instead of a 4? (But I agree that your professor's version seems off.)

 

[Abdu Ewais]

If I understand your question, shouldn't that be a 4/3 instead of a 4? (But I agree that your professor's version seems off.)

Sorry got it off by a bit there. fixed