I Problem with gravitation field perpendicular vector.

AI Thread Summary
The discussion centers on the confusion regarding the expression for the gravitational field perpendicular vector, specifically why it is represented as -R G ρ/3 for a perfect sphere with uniform mass distribution. Participants question whether it should instead be -4/3 π R G ρ, highlighting a potential error in the professor's formulation. There is agreement among contributors that the professor's version appears incorrect. Clarifications are made, indicating a slight misunderstanding in the calculations. The conversation emphasizes the importance of accurate gravitational field equations in physics.
Abdu Ewais
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since it is known that ##\vec{A_\perp} = -{mG \over R^2}## why did the professor write it as ##\vec{A_\perp} = {- R G \rho \over 3}## for perfect sphere with perfect mass distribution ? Shouldn't it be ##\vec{A_\perp} = -{4 \over 3} \pi R G \rho##? I need help thanks.
 
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If I understand your question, shouldn't that be a 4/3 instead of a 4? (But I agree that your professor's version seems off.)
 
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Doc Al said:
If I understand your question, shouldn't that be a 4/3 instead of a 4? (But I agree that your professor's version seems off.)
Sorry got it off by a bit there. fixed
 

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