Problem with gravitation field perpendicular vector.

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SUMMARY

The discussion centers on the gravitational field perpendicular vector, specifically the expression for gravitational acceleration due to a perfect sphere with uniform mass distribution. The original formula presented by the professor, ##\vec{A_\perp} = {- R G \rho \over 3}##, was questioned by participants who argued that it should be ##\vec{A_\perp} = -{4 \over 3} \pi R G \rho##. The confusion arose from the constants involved in the equations, highlighting the importance of precise mathematical representation in gravitational physics.

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Abdu Ewais
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since it is known that ##\vec{A_\perp} = -{mG \over R^2}## why did the professor write it as ##\vec{A_\perp} = {- R G \rho \over 3}## for perfect sphere with perfect mass distribution ? Shouldn't it be ##\vec{A_\perp} = -{4 \over 3} \pi R G \rho##? I need help thanks.
 
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If I understand your question, shouldn't that be a 4/3 instead of a 4? (But I agree that your professor's version seems off.)
 
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Doc Al said:
If I understand your question, shouldn't that be a 4/3 instead of a 4? (But I agree that your professor's version seems off.)
Sorry got it off by a bit there. fixed
 

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