Problem with Integral question

  • Thread starter Thread starter kasse
  • Start date Start date
  • Tags Tags
    Integral
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
1 reply · 1K views
kasse
Messages
383
Reaction score
1
If I know that [tex]\int^{\pi /2}_{0}x^2 cos^2 x dx = \frac{\pi^3}{48} - \frac{pi}{8}[/tex] can I use this to calculate [tex]\int^{\pi / 2}_{- \pi /2} u^2 cos^2 u du[/tex]?
 
Physics news on Phys.org


Obviously, since the integrand is even, the latter integral is just twice the first.