1. PF Contest - Win "Conquering the Physics GRE" book! Click Here to Enter
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Problem with Integral question

  1. Nov 16, 2008 #1
    If I know that [tex]\int^{\pi /2}_{0}x^2 cos^2 x dx = \frac{\pi^3}{48} - \frac{pi}{8}[/tex] can I use this to calculate [tex]\int^{\pi / 2}_{- \pi /2} u^2 cos^2 u du[/tex]?
  2. jcsd
  3. Nov 16, 2008 #2


    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    Dearly Missed

    Re: Integral

    Obviously, since the integrand is even, the latter integral is just twice the first.
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook