Problem with squares and roots

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The discussion focuses on solving the function f(x) = √(x+1)² - √(x-1)², where the user struggles with the concepts of squares and roots. The initial approach of simplifying the expression incorrectly assumes √x² = x instead of |x|. Clarification is provided that the function should be rewritten as f(x) = |x+1| - |x-1|, which requires analyzing different cases based on the value of x. The user gains understanding by considering the function's behavior in various regions, particularly for x < -1. The conversation emphasizes the importance of recognizing absolute values in mathematical expressions.
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Homework Statement



Hi, I am currently studying for a exam and I have noticed I have difficulty with squares and roots. I decided to take a problem from an exam so that I can illustrate the problems I am having with it.

Homework Equations



If f(x) = √(x+1)2 - √(x-1)2

(a) f(x) = 2; (b) f(x) = 2x; (c) f(x) = 2√x; (d) none of (a)-(c).

The Attempt at a Solution



My first instict is to remove the squares and the roots so that f(x) = x+1 - (x-1) which in turn gives me the answer (a). This is incorrect. I am guessing it has to do with the fact that x is not defined to be ≥ 0. Any help?
 
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BruceSpringste said:
My first instict is to remove the squares and the roots so that f(x) = x+1 - (x-1) which in turn gives me the answer (a). This is incorrect.

Remember √x2 = |x| and not simply x.Now rewrite f(x) .

BruceSpringste said:
I am guessing it has to do with the fact that x is not defined to be ≥ 0. Any help?

No.The domain of the function is R .
 
Last edited:
Tanya Sharma said:
Remember √x2 = |x| and not simply x.

Now rewrite f(x) .

f(x) = |x+1| - |x-1|

I'm a bit slow, where do I take it from here?
 
Good...

Now the function will be defined differently in different regions.First consider x<-1

What is the value of |x+1| when x<-1 ?
What is the value of |x-1| when x<-1 ?
What is the value of |x+1|-|x+1|when x<-1 ?
 
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Alright now I understand completely! Thank you very much!
 
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