Problem with two trigonometric integrals

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The discussion centers on the evaluation of the integrals of the functions sin²(nθ + ψ) and cos²(nθ + ψ) over the interval from 0 to 2π. It is established that both integrals equal π, regardless of the phase angle ψ. The consensus is that setting ψ to 0 is not necessary, as the bounds of integration (0 to 2π) ensure that the phase does not influence the integral's value. The periodic nature of the sine and cosine functions guarantees that the integral remains constant across different values of ψ.

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Belgium 12
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Hi

I have a little problem with the integrals of the following functions.

integral from 0to 2pi ∫sin^2(nθ+ψ)dθ=∫cos^2(nθ+ψ)dθ=pi

ψ=the phase angle.They occur in the theory of vibrations.

Is it appropriate to set ψ=0

Thank you
 
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In general probably not. But your bounds are 0-2pi so I would say that phase doesn't matter
 
And when I say that it doesn't matter, I mean that it won't affect the value of that integral. I think that 2*pi will be divisible by the period of both of those functions regardless of n.
 

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