Problems Involving Two Interacting Bodies and Friction

  • Thread starter Thread starter prosteve037
  • Start date Start date
  • Tags Tags
    bodies Friction
AI Thread Summary
The discussion focuses on understanding the methods for solving problems involving two interacting bodies with friction. The user is confused about how the total acceleration of the system relates to the individual accelerations of the bodies, particularly in scenarios where one body is on a frictionless surface. They inquire if determining the net force and total acceleration is essential for solving these types of problems. Additionally, the user references another example involving two boxes with different coefficients of friction, seeking clarification on the interaction forces and their impact on acceleration. The conversation emphasizes the importance of comprehending the underlying principles of motion and friction in these scenarios.
prosteve037
Messages
110
Reaction score
3

Homework Statement



I've already answered this question correctly after multiple tries but I am still confused about the method in solving these kind of problems.

The two blocks (m = 18 kg and M = 88 kg) in Fig. 6-38 are not attached to each other. The coefficient of static friction between the blocks is μs = 0.33, but the surface beneath the larger block is frictionless. What is the minimum magnitude of the horizontal force \vec{F} required to keep the smaller block from slipping down the larger block?

http://edugen.wileyplus.com/edugen/courses/crs4957/art/qb/qu/c06/fig06_36.gif

Homework Equations


Newton's Second Law: \textit{ƩF = ma}
Newton's Third Law: \textit{F}_{A}\textit{ + F}_{B}\textit{ = 0}

The Attempt at a Solution



For problems like these, why and how is it that the total acceleration is equal to the individual accelerations of the bodies?

Is it a crucial step in solving problems like these to find the net force and net/total acceleration of the two bodies?

-------------------------------------------------------------------------------

There was another question I read that showed the separate coefficients of friction (between the bodies and the ground) for two bodies on a surface (interacting/touching each other). Given one of the interacting forces between the two objects, would the net/total acceleration of the system still be the individual accelerations of the bodies?

Here's an example of this kind of problem that I'm talking about:

In the figure here, a box of Cheerios (mass mC = 1.4 kg) and a box of Wheaties (mass mW = 3.1 kg) are accelerated across a horizontal surface by a horizontal force applied to the Cheerios box. The magnitude of the frictional force on the Cheerios box is 2.6 N, and the magnitude of the frictional force on the Wheaties box is 4.8 N. If the magnitude of \vec{F} is 12.2 N, what is the magnitude of the force on the Wheaties box from the Cheerios box?

http://edugen.wileyplus.com/edugen/courses/crs4957/art/qb/qu/c06/fig_6_A.gif
 
Last edited:
Physics news on Phys.org
Again, I already completed these questions and am not asking for help in solving them. I just need clarification as to why the methods for solving them are as they are.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top