# Problems with calculating integrals

1. Jan 30, 2006

### zee_22

:!!) :rofl: This question simply says calculate
Question
[integral from 0 to t]xe^-xdx

this is one of the questions from my calculus online course there are no similar examples to this in the given notebookk
i have taken the first year calculus but forgot somestuff, this was 3 years ago, this is why i really need help!!!
Hints is fine as long of course they lead me to the solution.
This is what i thought i can do , rearrange the equation to somthing like x/e^x dx but now what if i use substitution say u= e^x then du= e^xdx
now the new limits would go like this whwen x= 0 then u= 1 and when the upper limit x=t then u=e^t i think so far so good, i hope someone can confirm the aligibility of this ??!!!
Then :
[integral from 0 to t]x/e^xdx
=[integral from 1 to e^t]x/u[1/e^x]du
now i dont know what to do:uhh: :uhh:

Another question:
is there a specific method for calculation integrals like this????
[integral from 2 to 3 ] 1/[x-1][x-4]dx
also [integral from 0 to 3] 1/([9-x^2]^1/2) dx
Last but not least is there a website anyoone suggests that has examples of such problems???Thank you for the help

Last edited: Jan 30, 2006
2. Jan 30, 2006

### arildno

For your first, use integration by parts.
For your second, use partial fractions decomposition.
For your third, use the substitution $$x=3\sin(u)$$

3. Jan 30, 2006

### Jameson

Tabular also works for the first one, if you're familiar with this method. It uses by parts, but it's less time consuming.

4. Jan 31, 2006

### HallsofIvy

Staff Emeritus
x/e^x= xe^(-x) doesn't it? Looks like a good candidate for integration by parts.