Processing 0.25% Silver Ore to Obtain 2 Pounds

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To obtain 2.0 pounds of silver from ore containing 0.25% silver by mass, the calculations must account for the conversion of pounds to grams, where 1 pound equals 454 grams. The correct decimal representation of 0.25% is 0.0025, which is crucial for accurate calculations. The density of the ore is 7.0 g/cm³, which impacts the volume needed to extract the desired amount of silver. The initial answer of 520 was significantly off due to a miscalculation, leading to the correct requirement of 52,000 cm³ of ore. Understanding these conversions and percentages is essential for solving similar problems accurately.
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How many cubic centimeters of ore 0.25% by mass silver must be processed to obtain 2.0 pounds of silver? The density of the ore is 7.0 g/cm cubed. cm cubed; 1.00 pound=454 g. Assume that the process is 100% efficient.

I get the answer of 520 but the answer is 52000 and i don't understand why I am so off. Can someone help me please i would really appreciate it.


Thank you :smile:
 
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This is just a guess, but since your answer is off by a factor of 100, I bet the problem came when you did not divide .25% by 100 in your calculations (.25% = .0025 in decimal form).
 

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