Product of compact sets compact in box topology?

[spicychicken]

So Tychonoff theorem states products of compact sets are compact in the product topology.

is this true for the box topology? counterexample?

 

[micromass]

A counterexample is \prod_{n\in \mathbb{N}}{[0,1]}. Can you show why?

 

[spicychicken]

if S_n is the set with empty sets in each index except n where for index n you have [0,1], then {S_n} is an open cover with no finite subcover...i think

 

[micromass]

if S_n is the set with empty sets in each index except n where for index n you have [0,1], then {S_n} is an open cover with no finite subcover...i think

Such a sets will always be empty. Try to consider a cover by all sets of the form

\prod_{n\in \mathbb{N}}{A_i}

Where A_i=[0,0.6[ or A_i=]0.5,1]