Projectile height formula based on distance?

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A formula to determine a projectile's height at a specified distance from its launch point or target base is sought, focusing on ground distance rather than time. The discussion highlights the influence of drag and lift on the trajectory, suggesting that these factors will alter the symmetry of the path. The user aims to derive height as a function of distance using known parameters like initial velocity, lift, and drag. The approach involves finding height and distance functions, then substituting to express height in terms of distance. The complexity of the algebra is acknowledged, but the user is encouraged to pursue the calculations.
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If a projectile shot from the ground were shot at a target located at a specified height above the ground, and would hit the target, is there a known formula to find the projectile’s height on its trajectory a specified distance (measured along the flat ground) from the target’s base or from the projectile’s launch point (which is on the ground)? I’m hoping for something based on the distance along the ground rather than on time. I have some rough numbers to use for drag and for lift and numbers for angle and velocity. Seems to me the drag and lift would prevent the trajectory from being the same shape on both sides of the trajectory’s highest point. The entire trajectory would occur over a flat surface.
 
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So you know trajectory, initial velocity, lift and drag, so you should be able to find h(t) and d(t) where h = height and d = distance. Using these two functions, you can hold t fixed and find t = f(d). Then plug f(d) back into your equation for h(t), giving h(f(d)).
It might get complicated in the algebra, but should not be too hard.
 
Thanks. I'll try to give that a try.
 
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