Projectile Motion: Find Speed & Displacement in 2s

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The problem involves a rock launched horizontally from a cliff at 5 m/s, with gravity set at 10 m/s². After 2 seconds, the horizontal speed remains 5 m/s, while the vertical displacement can be calculated using the equation for motion under constant acceleration. The rock's horizontal distance from the cliff edge can be determined by multiplying its speed by the time. Participants are encouraged to share their attempts at solving the problem for further assistance. The discussion aims to clarify the calculations for speed and displacement in projectile motion.
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Homework Statement




At time t = 0 s, a large rock is launched horizontally from a tall cliff at 5 m/s. Define a coordinate system with its origin located at the edge of the cliff, its x-axis aligned with the initial velocity of the rock, and its y-axis pointing upwards. Take the acceleration of gravity to be exactly 10m/s² (rather than 9.8 m/s²) to simplify the mathematics.

a) How fast is the rock traveling and how many meters away from the edge of the cliff is the rock after 2 seconds?

b) Complete the attached table (check the attached file)

Homework Equations



y=yi + Vyi △t +1/2ay △t²

The Attempt at a Solution

 

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Hi kevin948! Welcome to PF! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 

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